2x^(2/3)-9x^(1/3)-5=0

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Solution for 2x^(2/3)-9x^(1/3)-5=0 equation: 


x in (-oo:+oo)

2*x^(2/3)-(9*x^(1/3))-5 = 0

2*x^(2/3)-9*x^(1/3)-5 = 0

t_1 = x^(1/3)

2*t_1^2-9*t_1^1-5 = 0

2*t_1^2-9*t_1-5 = 0

DELTA = (-9)^2-(-5*2*4)

DELTA = 121

DELTA > 0

t_1 = (121^(1/2)+9)/(2*2) or t_1 = (9-121^(1/2))/(2*2)

t_1 = 5 or t_1 = -1/2

t_1 = -1/2

x^(1/3)+1/2 = 0

1*x^(1/3) = -1/2 // : 1

x^(1/3) = -1/2

( -1/2 < 0 i 1/3 in (0:1) ) => x należy do O

t_1 = 5

x^(1/3)-5 = 0

1*x^(1/3) = 5 // : 1

x^(1/3) = 5

x^(1/3) = 5 // ^ 3

x = 125

x = 125

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